The balanced net ionic equation for the reaction of calcium chloride and sodium phosphate contains which of the following terms?

3 {C a}_{(a q)}^{2 +}

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{P O}_{4 (a q)}^{3 -}

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2 {C a}_{3} {({P O}_{4})}_{2 (s)}

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6 N a {C l}_{(a q)}

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Solution

The correct option is A $3 {C a}_{(a q)}^{2 +}$
Your unbalanced equation is
$N a_{3} P O_{4}$ + $C a C l_{2}$ $\to$ $C a_{3} (P O 4)_{2}$ + $N a C l$
Step 1. Start with the most complicated formula, $C a_{3} (P O 4)_{2}$ ,
Put a 1 in front of it. we have now fixed the number of $C a_{2}$ atoms and $P O_{4}$ groups
$N a_{3} P O_{4}$ + $C a C l_{2}$ $\to$ $C a_{3} (P O 4)_{2}$ + $N a C l$
Step 2. Balance Ca put 3 in front of $C a C l_{2}$
$N a_{3} P O_{4}$ + $3 C a C l_{2}$ $\to$ $1 C a_{3} (P O 4)_{2}$ + $N a C l$
Step 3. Balance $P O_{4}$ . put a 2 in front of $N a_{3} P O_{4}$
$2 N a_{3} P O_{4}$ + $3 C a C l_{2}$ $\to$ $1 C a_{3} (P O 4)_{2}$ + $N a C l$
Step 4. Balance Na put a 6 in front of $N a C l$
$N a_{3} P O_{4}$ + $3 C a C l_{2}$ $\to$ $1 C a_{3} (P O 4)_{2}$ + $6 N a C l$
The equation should be balanced. Let's check
$N a_{3} P O_{4}$ + $3 C a C l_{2}$ $\to$ $1 C a_{3} (P O 4)_{2}$ + $N a C l$
Ans. $3 C a^{2 +} a q$

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