The ball hits a wall horizontally at 6 m s^_1. it rebounds horizontally at 4.4 m s^_1. The ball is in contact with the Wall for 0.04 s . what is acceleration of the ball

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Solution

Initial velocity = 6 m/s ( forward)

final velocity = 4.4 m/s ( backward) = -4.4 m/s ( forward )

acceleration = change in velocity/time

= ( -4.4 -6)/ 0.04 = -10.4/0.04

= -1040/4 = -260 m/s² ( forward )

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The ball hits a wall horizontally at 6 m s_1 . it rebounds horizontally at 4.4 m s_1. The ball is in contact with the Wall for 0.04 s . what is acceleration of the ball

Initial velocity = 6 m/s ( forward) final velocity = 4.4 m/s ( backward) = -4.4 m/s ( forward ) acceleration = change in velocity/time = ( -4.4 -6)/ 0.04 = -10.4/0.04 = -1040/4 = -260 m/s² ( forward )

The ball hits a wall horizontally at 6 m s^_1. it rebounds horizontally at 4.4 m s^_1. The ball is in contact with the Wall for 0.04 s . what is acceleration of the ball

Initial velocity = 6 m/s ( forward)

final velocity = 4.4 m/s ( backward) = -4.4 m/s ( forward )

acceleration = change in velocity/time

= ( -4.4 -6)/ 0.04 = -10.4/0.04

= -1040/4 = -260 m/s² ( forward )