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Question
The barrier potential in a p-n junction is 0.3 V. The current required is 6 mA. The emf of the cell required for use in the circuit if a resistance of 200Ω is connected in series with junction is
The barrier potential in a p-n junction is 0.3 V. The current required is 6 mA. The emf of the cell required for use in the circuit if a resistance of 200Ω is connected in series with junction is
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Solution
The correct option is B 1.5 V
Given that:
VD=0.3 V
I=6 mA=0.006 A
R=200Ω
Here we can write,
E−VD=IR
where, E is the emf of battery
E=IR+VD
E=(0.006×200)+0.3
E=1.2+0.3=1.5 V
Given that:
VD=0.3 V
I=6 mA=0.006 A
R=200Ω
Here we can write,
E−VD=IR
where, E is the emf of battery
E−VD=IR
where, E is the emf of battery
E=IR+VD
E=(0.006×200)+0.3
E=1.2+0.3=1.5 V
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