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Atmospheric Pressure

The base of a...

Question

The base of a cylindrical vessel measures $300 c m^{2}$ , water is poured into it up to a depth of 6cm. Calculate the pressure of water on the base of the vessel. ( g=10 $m / s^{2}$ ; density of water = 1000 $k g / m^{3}$ )

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Solution

Hydraulic pressure = $ϱ g h = 1000 \times 10 \times \frac{6}{100}$
Hydraulic pressure = 600 Pascal

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300 c m^{2}

6 c m

ρ_{w} = 1000 k g / m^{3}

g = 10 m / s^{2}

c m^{2}

The area of base of a cylindrical vessel is 300cmsquare water (density = 1000kg m-3 ) is poured into it up to a depth of 6cm.

Calculate

The pressure

The thrust of water on the base.(g=10ms-2)

300 {c m}^{2}

6 c m

= 1000 k g

m^{- 3}

g = 10 m

s^{- 2}

300 c m^{2}

1000 k g m^{- 3}

6 c m

g = 10 m s^{- 2}

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