The base of an isosceles triangle is $24$ cm and its area is $192$ sq. cm. Find its perimeter.

64

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60

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63

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62

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Solution

The correct option is A $64$ cm
Given, base of an isosceles triangle $= 24 c m$
Area of isosceles triangle $= 192 s q . c m$

Area $=$ $\frac{1}{2} \times b \times h$

$∴ 192 = \frac{24. h}{2}$

$∴ h = 16 c m$

Side= $\sqrt{h^{2} + 12^{2}} = \sqrt{256 + 144} = 20 c m$

Perimeter of triangle $= 2 a + b$
$= 2 (20) + 24 = 64 c m$

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