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Density

The base of c...

Question

The base of cylindrical vessel measures 300 $c m^{2}$ . Water is poured into it up to a depth of 6 cm. Calculate the pressure of water on the base in vessel.

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Solution

We already know that $p = ρ$ gh where

$ρ$ = density of water =1000kg/ $m^{2}$

g= acceleration due to gravity = 10m $s^{- 2}$

h=height=6cm=0.06m

As $p = ρ g h = 1000 \times 10 \times 0.06$

$600 k g m^{- 1} s^{- 2} = 600 P a$

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Similar questions

300 c m^{2}

m / s^{2}

k g / m^{3}

The area of base of a cylindrical vessel is 300cmsquare water (density = 1000kg m-3 ) is poured into it up to a depth of 6cm.

Calculate

The pressure

The thrust of water on the base.(g=10ms-2)

300 c m^{2}

6 c m

ρ_{w} = 1000 k g / m^{3}

g = 10 m / s^{2}

300 c m^{2}

1000 k g m^{- 3}

6 c m

g = 10 m s^{- 2}

300 {c m}^{2}

6 c m

= 1000 k g

m^{- 3}

g = 10 m

s^{- 2}

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