Question

The batting average for 50 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 162 runs. If these two innings are excluded, the average becomes 48 runs. What is the lowest score of the player?

• A. 18
• B. 20
• C. 16
• D. 17
• E. 15

Answer 1

The correct option is D

17

Total runs scored by the player in 50 innings =50$\times$50

Total runs scored by the player in 48 innings after excluding two innings= 48$\times$48

Sum of the scores of the excluded innings =(50 $\times$ 50) -- (48 $\times$ 48) = 196.

Given that the scores of the excluded innings differ by 162. Hence let's take the lowest score as x and highest score as x + 162.

Now x + 162 + x = 196

$\Rightarrow$ 2x = 34

$\Rightarrow$x = 17

Lowest score = 17.