The batting scores of two cricket players A and B in 10 innings are as follows :-
Batsman A 15 17 19 27 30 36 40 90 95 110
Batsman B 10 16 21 28 37 41 36 80 82 65
Find which of the player is more consistent.

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Solution

the player with less standard deviation i more consistant ,

Mean runs of A = ${¯ x}_{A}$ =47.9.

Mean runs of B = ${¯ x}_{B}$ =41.6

we know,

Mean deviation (A)= $\sqrt{\sum_{t = 1}^{10}} \frac{f i - {¯ x}_{A}}{10}$

$∴$ Mean deviation $(A) = 34.177$

Mean deviation $(B) = 7.727$

$∴$ player B is more consistent.

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The batting scores of two cricket players A and B in 10 innings are as follows :-Batsman A151719273036409095110Batsman B10162128374136808265Find which of the player is more consistent.

the player with less standard deviation i more consistant , Mean runs of A = ¯xA=47.9. Mean runs of B = ¯xB=41.6 we know, Mean deviation (A)= √∑10t=1fi−¯xA10 ∴ Mean deviation (A)=34.177 Mean deviation (B)=7.727∴ player B is more consistent.

The batting scores of two cricket players A and B in 10 innings are as follows :-
Batsman A 15 17 19 27 30 36 40 90 95 110
Batsman B 10 16 21 28 37 41 36 80 82 65
Find which of the player is more consistent.