Question

The below PMMC meter is connected in the circuit shown in the adjoining figure. The opamp is ideal. The voltage $V\left(t\right)=3sin314tV.$ Assuming the source impedance of V(t) to be zero, the ammeter will indicate a current of _____$\mu A.$

• A. 190.9
• B. 19
• C. 200
• D. 0.19

Answer 1

The correct option is A 190.9

$\text{Current through the}10k\Omega \text{resistor}$

$=\frac{3}{10\times {10}^3}sin314t=(3\times {10}^{-4})sin314t$

Current flowing through the meter is shown below,


$\therefore \text{Reading of PMMC meter}$

$=\frac{2V_m}{\pi }=\frac{2\times 3\times {10}^{-4}}{\pi }=190.9\mu A$