The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with:

{P C l}_{3}

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{P C l}_{5}

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{S O C l}_{2}

in presence of pyridine

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dry

H C l

in the presence of anhydrous

{Z n C l}_{2}

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Solution

The correct option is D ${S O C l}_{2}$ in presence of pyridine
The best method for the conversion of an alcohol to alkyl chloride is by treating the alcohol with $S O C l_{2}$ in the presence of pyridine.

$R O H + S O {C l}_{2} ⟶ R C l + H C l + S O_{2}$
The formed products leave the alkyl chloride as they are gases and hence pure alkyl chloride is obtained.

So, the correct option is $C$

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