The best method to prepare neopentyl chloride is:

(C H_{3})_{3} C C H_{2} O H P C l_{5}, Δ ⟶

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(C H_{3})_{3} C C H_{2} O H H C l, Δ ⟶

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(C H_{3})_{3} C C H_{2} O H S o C l_{2}, p y r i d i n e ⟶

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(C H_{3})_{3} C C H_{3} C l_{2}, h ν Δ ⟶

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Solution

The correct option is D $(C H_{3})_{3} C C H_{3} C l_{2}, h ν Δ ⟶$
Neopentylalcohol on reaction with $H C l$ on heating forms 2-methyl-2-chlorobutane.
So the answer is option D.

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Similar questions

Q. Because of the great tendency of the neopentyl cation to rearrange, neopentyl chloride can not be prepared from the alcohol. How might neopentyl chloride be prepared?

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Q. The preparation of ethyl chloride from ethyl alcohol with thionyl chloride is carried in the presence of pyridine. Here, pyridine is used because:

C H_{3} C H O + C H_{2} (C O O H)_{2} △ - --- \to P y r i d i n e X; X

is :

The thionyl chloride method is preferred over hydrogen chloride or phosphorous chloride method for the preparation of haloalkanes because both the by-products (SO₂ and HCl) in this case are gases and escape leaving behind pure chloroalkane. This reaction takes place in the presence of

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The best method to prepare neopentyl chloride is:

The correct option is D (CH3)3CCH3Cl2,hνΔ⟶Neopentylalcohol on reaction with HCl on heating forms 2-methyl-2-chlorobutane.So the answer is option D.

The correct option is D $(C H_{3})_{3} C C H_{3} C l_{2}, h ν Δ ⟶$
Neopentylalcohol on reaction with $H C l$ on heating forms 2-methyl-2-chlorobutane.
So the answer is option D.