The best oxidising agent for oxidation of $C H_{3} - C H = C H - C H O$ to $C H_{3} - C H = C H - C O O H$ is :

Baeyer's reagent

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Tollens' reagent

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Schiff's reagent

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Acidified dichromate

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Solution

The correct option is B Tollens' reagent
Since dichromates are powerful oxidising agents, they can oxidize double bond also, to protect double bond, we use mild oxidising agent as Tollen's $[A g (N H_{3})_{2}]^{+} O H^{-}$ which oxidises aldehyde to acids and $A g^{(0)}$ (mirror) is precipitated.

Option B is correct.

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Similar questions

C H_{3} - C H = C H - C H_{2} O H \to C H_{3} - C H = C H - C O O H

C H_{3} - C H = C H - C H_{2} - O H | C H - C H_{3} ⟶ C H_{3} - C H = C H - C H_{2} - C O O H

C H_{3} - O | | C - C H | C H_{3} - C H | C H O - C H | C H_{3} - C H_{3}

C H_{3} - C H = C H - C O O H \to C H_{3} - C H = C H - C H_{2} O H

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