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Standard IX

Physics

Nuclear Stability

The binding e...

Question

The binding energies of nuclei $X$ and $Y$ are $E_{1}$ and $E_{2}$ respectively. Two atoms of $X$ fuse to give one atom of $Y$ and an energy $Q$ is released. Then

Q = 2 E_{1} - E_{2}

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Q = E_{2} - 2 E_{1}

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Q = 2 E_{1} + E_{2}

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Q = 2 E_{2} + E_{1}

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Solution

The correct option is B $Q = E_{2} - 2 E_{1}$
Given Reaction can be considered as
$X + X \to Y + Q$
Heat released
$Q = B E_{P} - B E_{R}$
$Q = E_{2} - 2 E_{1}$

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The binding energies of nuclei X and Y are E1 and E2 respectively. Two atoms of X fuse to give one atom of Y and an energy Q is released. Then

The correct option is B Q=E2−2E1Given Reaction can be considered as X+X→Y+Q Heat released Q=BEP−BER Q=E2−2E1

The binding energies of nuclei $X$ and $Y$ are $E_{1}$ and $E_{2}$ respectively. Two atoms of $X$ fuse to give one atom of $Y$ and an energy $Q$ is released. Then

The correct option is B $Q = E_{2} - 2 E_{1}$
Given Reaction can be considered as
$X + X \to Y + Q$
Heat released
$Q = B E_{P} - B E_{R}$
$Q = E_{2} - 2 E_{1}$