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Bohr's Model of a Hydrogen Atom

The binding e...

Question

The binding energies of the atom of elements A and B are $E_{a}$ and $E_{b}$ respectively. Three atoms of the element B fuse to give one atom of element A. This fusion process is accompanied by release of energy $e$ . Then $E_{a}, E_{b}$ are related to each other as

E_{a} + e = 3 E_{b}

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E_{a} = 3 E_{b}

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E_{a} - e = 3 E_{b}

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E_{a} + 3 E_{b} + e = 0

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Solution

The correct option is A $E_{a} + e = 3 E_{b}$
Binding energy of three $B$ elements will be $3 E_{b}$ So, by energy conservation, binding energy of three $B$ elements is equal to the sum of $A$ element's binding energy and the released energy.
o, equation is $E_{a} + e = 3 E_{b}$

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