Question

The binding energy of a deuteron $H^2$ is 1.15 MeV per nucleon & that of an alpha particle is 7.1 Mev per nucleon. Then in the reaction $H^2+H^2\to H{e}^4+Q,$ the energy Q released is approximately

• A. 1 MeV
• B. 200 MeV
• C. 10 MeV
• D. 23.8 MeV

Answer 1

The correct option is D

23.8 MeV

$H^2+H^2\to H{e}^4+Q$

Total BE on $LHS=2\times (2\times 1.15)=4.60MeV$

Total BE on $RHS=4\times 7.1=28.4MeV$

$\therefore Q=28.4–4.6=23.8MeV$