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Binding Energy

The binding e...

Question

The binding energy per nucleon for $_{6} C^{12}$ is $7.68 M e V$ and that for $_{6} C_{13}$ is $7.47 M e V$ . Calculate the energy required to remove a neutron from $_{6} C_{13}$ .

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Solution

Any atom has a nucleus around which electrons are revolving.
Every nucleon consists of at least one proton. Many nuclei have some neutrons in them along with protons.
Protons and neutrons are together called as nucleons.
Binding energy (BE) is the amount of energy required break the nucleus and separate all the nucleons.
BE per nucleon is given by $B E / A = \frac{B E}{A}$ Here $A$ is the number of nucleons in the atom.
$_{6} C_{13}$ means that there are 6 protons, 13 nucleons and 13-6=7 neutrons
Energy required to remove one neutron will be equal to BE per nucleon=7.47MeV

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