Question

The binding energy per nucleon for ${}_{92}^{235}U$ is 7.5 MeV and for the nuclei of having half mass is 8.5 MeV. If ${}_{92}^{235}U$ undergoes nuclear fission in two such nuclei of equal size, how much energy is released in the process?

• A. 235 MeV
• B. 435 MeV
• C. 255 MeV
• D. None of these

Answer 1

The correct option is A 235 MeV

The binding energy per nucleon for ${}_{92}^{235}U$ is $7.5$ MeV and $8.5$ MeV for nuclei of half that mass.

If${}_{92}^{235}U$ undergoes nuclear fission in two such nuclei of equal size, then since $235$ nucleons are involved, each will release $8.5-7.5=1$ MeV energy

So, the total energy liberated will be = $235\times 1=235$ MeV