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Law of Radioactivity

The binding e...

Question

The binding energy per nucleon for $C^{12}$ is $7.68 M e V$ and that for $C^{13}$ is $7.5 M e V$ . The energy required to remove a neutron from $C^{13}$ is

5.34 M e V

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5.5 M e V

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9.5 M e V

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9.34 M e V

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Solution

The correct option is A $5.34 M e V$
Energy required to remove a neutron from $C^{13} = B . E o f C^{13} - B E o f C^{12} = 7.5 \times 13 - 7.68 \times 12 = 97.5 - 92.16 = 5.34 M e V$

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