The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ .Then

E_{2} = 2 E_{1}

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E_{1} > E_{2}

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E_{2} > E_{1}

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E_{1} = 2 E_{2}

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Solution

The correct option is C $E_{2} > E_{1}$
After decay, the daughter nuclei will be more stable hence binding energy per nucleon will be more than that of their parent nucleus.

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A nucleus of mass $M + △ m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $c$ .
The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ . Then

Q. A nucleus of mass

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is at rest and decays into two daughter nuclei of equal mass

\frac{M}{2}

each. Speed of light is

c

. The binding energy per nucleon for the parent nucleus is

E_{1}

and that for the daughter nuclei is

E_{2}

. Then :

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is at rest and decays into two daughter nuclei of equal mass

\frac{M}{2}

each. Speed of light is

c

.
The binding energy per nucleon for the parent nucleus is

E_{1}

and that for the daughter nuclei is

E_{2}

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[AIEEE-2010]

No/2 atoms of $X_{(g)}$ are converted into $X_{(g)^{+}}^{+}$ by energy $E_{1}$ , No/2 atoms of $X_{g}$ are converted into $X_{(g)}^{-}$ by energy $E_{2}$ . Hence ionization potential and electron affinity of $X_{(g)}$ per atom are

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The binding energy per nucleon for the parent nucleus is E1 and that for the daughter nuclei is E2.Then

The correct option is C E2>E1After decay, the daughter nuclei will be more stable hence binding energy per nucleon will be more than that of their parent nucleus.

The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ .Then

The correct option is C $E_{2} > E_{1}$
After decay, the daughter nuclei will be more stable hence binding energy per nucleon will be more than that of their parent nucleus.