Question

The bond angle and hybridization in ammonia is:

• A. ${109}^o{5}^{\prime },s{p}^3$
• B. ${104}^o{31}^{\prime },s{p}^3$
• C. ${107}^o,s{p}^3$
• D. none of these

Answer 1

Answer: (C)

${107}^o,s{p}^3$

Hybridization in ammonia is $s{p}^3$ is formed by the overlapping of three half filled orbitals of nitrogen atom with $s$ orbital of $3$ hydrogen atom and angle is ${107}^{\circ }$ because of pyramidal or distorted tetrahedral due to presance of lone pair.