The bond angle around the central atom is highest in :

{S O}_{2}

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{B B r}_{3}

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{C S}_{2}

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{S F}_{4}

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Solution

The correct option is D ${S F}_{4}$
Bond angle is determined by the hybridization.
$S O_{2}$ undergo $s p^{3}$ hybridization and exhibits $109^{o}$ bond angle
$B B r_{3}$ undergo $s p^{2}$ hybridization and exhibits $120^{o}$ bond angle
$C S_{2}$ undergo $s p$ hybridization and exhibits $180^{o}$ bond angle.
$S F_{4}$ undergo $s p^{3} d$ hybridization and exhibits different bond angles.
So, the least bond angle is exhibited by $C S_{2}$ .
Hence, option D is correct.

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Similar questions

Q. Bond angle is defined as the angle between the orbitals containing bonding electron pairs around the central atom in a molecule

Q. Which of these molecules have non-bonding electron pairs on the central atom?
I :

S F_{4}

II :

I C l_{3}

III:

S O_{2}

Bond angle is the average angle between orbitals containing ___________ electron pairs around the central atom in a molecule.

Bond angle is defined as the angle between the orbitals containing bonding electron pairs around the central atom in a molecule/complex ion. (True/False)

Q. Assertion :In

S O_{2}

, the bond angle is

119^{\circ}

whereas in

S O_{3}

, the bond angle is

120^{\circ}

. Reason:

S

atom in both

S O_{2}

and

S O_{3}

s p^{2}

-hybridized.

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