The bond angles of a molecule having trigonal bipyramidal geometry are:

180°, 60°

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90°, 90°

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120°, 90°

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100°, 120°

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Solution

The correct option is C
120°, 90°

When a molecule has trigonal bipyramidal geometry bond angles are 120°, 90°.

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Similar questions

X -^M - X (90^{\circ})

The bond angle of a molecule undergoing sp² hybridisation is:

[M L_{5}]

90^{0}, 120^{0}

180^{0} L - M - L

P C l_{5}

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