The bond between carbon atom 1 and carbon atom 2 in compound N-1C-2CH-CH2 involves the hybridisation as

N≡1C 2CH=CH_2 Carbon bonded with a triple bond (i.e. nbsp; C_1) is sp hybridised. Carbon bonded with a double bond (i.e. nbsp;C_2) is sp^2 hybridised. Hence t ...

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Standard XII

Chemistry

Carboxylic Acid

The bond betw...

Question

The bond between carbon atom (1) and carbon atom (2) in compound $N \equiv C 1 - C H 2 = C H_{2}$ involves the hybridisation as

s p^{2} a n d s p^{2}

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s p^{3} a n d s p

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s p a n d s p^{2}

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s p a n d s p

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Solution

The correct option is C $s p a n d s p^{2}$
$N \equiv C 1 - C H 2 = C H_{2}$
Carbon bonded with a triple bond (i.e. $C_{1})$ is $s p$ hybridised. Carbon bonded with a double bond (i.e. $C_{2})$ is $s p^{2}$ hybridised. Hence the correct answer is option (c).

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Carboxylic Acid

Standard XII Chemistry

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The bond between carbon atom (1) and carbon atom (2) in compound N≡C1−CH2=CH2 involves the hybridisation as

The correct option is C sp and sp2N≡C1−CH2=CH2 Carbon bonded with a triple bond (i.e. C1) is sp hybridised. Carbon bonded with a double bond (i.e. C2) is sp2 hybridised. Hence the correct answer is option (c).

The bond between carbon atom (1) and carbon atom (2) in compound $N \equiv C 1 - C H 2 = C H_{2}$ involves the hybridisation as

The correct option is C $s p a n d s p^{2}$
$N \equiv C 1 - C H 2 = C H_{2}$
Carbon bonded with a triple bond (i.e. $C_{1})$ is $s p$ hybridised. Carbon bonded with a double bond (i.e. $C_{2})$ is $s p^{2}$ hybridised. Hence the correct answer is option (c).