Question

The bond between carbon atom (1) and carbon atom (2) in compound $N\equiv \underset{1}{C}-\underset{2}{CH}=C{H}_2$ involves the hybridisation as

• A. $s{p}^{2}ands{p}^2$
• B. $s{p}^{3}andsp$
• C. $spands{p}^2$
• D. $spandsp$

Answer 1

The correct option is C $spands{p}^2$

$N\equiv \underset{1}{C}-\underset{2}{CH}=C{H}_2$
Carbon bonded with a triple bond (i.e. $C_1)$ is $sp$ hybridised. Carbon bonded with a double bond (i.e. $C_2)$ is $s{p}^2$ hybridised. Hence the correct answer is option (c).