The bond disscioation energies of molecules $A_{2}, B_{2} a n d C_{2}$ are 945, 158, 498KJ/ mole respectively.if so, the correct decreasing order of their bond orders is

$A_{2}, C_{2} , B_{2}$

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$A_{2}, B_{2} , C_{2}$

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$B_{2}, C_{2} , A_{2}$

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$B_{2}, A_{2} , C_{2}$

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Solution

The correct option is A
$A_{2}, C_{2} , B_{2}$

Higher the bond order , higher the dissociation energy

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A_{2}, B_{2}, C_{2}

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