The bond dissociation of the molecules $A_{2}, B_{2}, C_{2}$ are $498, 158, 945 k J / m o l e$ respectively. If so, the correct decreasing order of their bond order is:

A_{2}, B_{2}, C_{2}

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C_{2}, B_{2}, A_{2}

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C_{2}, A_{2}, B_{2}

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B_{2}, C_{2}, A_{2}

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Solution

The correct option is D $C_{2}, A_{2}, B_{2}$
If bond dissociation energy is more , then bond order will be more. Because more energy is required to break bonds of high bond order.
So bond dissociation energy order is $C_{2} > A_{2} > B_{2}$
Similarly decreasing order of bond order is $C_{2}, A_{2}, B_{2}$

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The bond disscioation energies of molecules $A_{2}, B_{2} a n d C_{2}$ are 945, 158, 498KJ/ mole respectively.if so, the correct decreasing order of their bond orders is

If a + b + c = 2s, then prove the following identities

(a) s² + (s − a)² + (s − b)² + (s − c)² = a² + b² + c²

(b) a² + b² − c² + 2ab = 4s (s − c)

(d) a² − b² − c² + 2ab = 4(s − b) (s − c)

(e) (2bc + a² − b² − c²) (2bc − a² + b² + c²) = 16s (s − a) (s − b) (s − c)

(f)

Q. Simplify:

\frac{a^{2} - {(b - c)}^{2}}{{(a + c)}^{2} - b^{2}} + \frac{b^{2} - {(a - c)}^{2}}{{(a + b)}^{2} - c^{2}} + \frac{c^{2} - {(a - b)}^{2}}{{(b + c)}^{2} - a^{2}}

Q. If

△ = ⎡ ⎢ ⎣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ⎤ ⎥ ⎦

and

A_{2}, B_{2}, C_{2}

are respectively cofactors of

a_{2}, b_{2}, c_{2}

then

a_{1} A_{2} + b_{1} B_{2} + c_{1} C_{2}

is equal to ?

|\begin{matrix} - a (b^{2} + c^{2} - a^{2}) & 2 b^{3} & 2 c^{3} \\ 2 a^{3} & - b (c^{2} + a^{2} - b^{2}) & 2 c^{3} \\ 2 a^{3} & 2 b^{3} & - c (a^{2} + b^{2} - c^{2}) \end{matrix}| = a b c {(a^{2} + b^{2} + c^{2})}^{3}

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The bond dissociation of the molecules A2,B2,C2 are 498,158,945 kJ/mole respectively. If so, the correct decreasing order of their bond order is:

The correct option is D C2,A2,B2If bond dissociation energy is more , then bond order will be more. Because more energy is required to break bonds of high bond order.So bond dissociation energy order is C2>A2>B2Similarly decreasing order of bond order is C2,A2,B2

The bond dissociation of the molecules $A_{2}, B_{2}, C_{2}$ are $498, 158, 945 k J / m o l e$ respectively. If so, the correct decreasing order of their bond order is: