Question

The bond length of HCl bond is $2.29\times {10}^{-10}m$ . The percentage ionic character of HCl, if measured dipole moment is $6.226\times {10}^{-30}C.m$ is

• A. $8\%$
• B. $20\%$
• C. $17\%$
• D. $50\%$

Answer 1

The correct option is C

$17\%$

${\mu }_{cal}=e\times d$

= $1.6\times {10}^{-19}\times 2.29\times {10}^{-10}$

= $3.664\times {10}^{-29}C.m$

$\therefore \%$ ionic character = $\frac{{\mu }_{exp}}{{\mu }_{cal}}\times 100$

= $\frac{6.226\times {10}^{-30}}{3.664\times {10}^{-29}}\times 100=17\%$