The bond order of carbonyl $(C - O)$ bond after back-bonding:

Increases.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Decreases.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Remains constant.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Cannot be predicted.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Decreases.
Synergic bonding interactions are present in metal carbonyls. The sigma bond is formed when lone pair of electrons of carbonyl carbon is donated to vacant orbital of metal. To form a pi bond, an electron pair donated from filled metal d orbital to vacant anti bonding pi orbital of $C O$ . This involves lateral overlap of orbitals. Due to this the electron density in the bonding pi orbitals of $C O$ decreases and antibonding pi orbitals increases. This decreases the bond order.

Suggest Corrections

Similar questions

The correct statement regarding O $_{2}$ $^{+}$ is

[M n (C O)_{6}]^{+}, [T i (C O)_{6}], [C r (C O)_{6}]

[V (C O)_{6}]^{-}

C - O

Join BYJU'S Learning Program