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The bond orde...

Question

The bond order of NO molecule is

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2.5

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Solution

The correct option is C
2.5

B.O, = $\frac{N o . o f b o i l i n g e^{-} - N o . o f a n t i b o n d i n g e^{-}}{2}$

$= \frac{8 - 3}{2} = \frac{5}{2} = 2.5$ .

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Similar questions

The bond order of NO molecule is

[MP PET 1996]

2.5

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