The bond order of the species with orbital configuration -1 s2- 1 s2-2 s2-2 s 2-2 pz 1 willbeA- 1 - 2B- 2C- 3D- Zero

The correct option is A 1/2 Bond order =number of electrons in B. M.O number of electrons in A.B.M.O/2 ...

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Molecular Orbital Energy Diagrams

The bond orde...

Question

The bond order of the species with orbital configuration ( $σ$ $_{1 s}$ ) $^{2}$ ( $σ$ $^{}$ $_{1 s}$ ) $^{2}$ .( $σ$ $_{2 s}$ ) $^{2}$ ( $σ$ $^{}$ $_{2 s}$ ) $^{2}$ ( $σ$ $^{*}$ $_{2 p z}$ ) $^{1}$ will
be

1/2

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Zero

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