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Question

The bond orders of O22,O2,O2 are respectively x, y and z.

Then what is the value of 2(x+y+z)?

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Solution

The bond orders of O22,O2,O2 are respectively x,y and z

Bond order of O2 = 2

Bond order of O2 = 1.5

Bond order of O22 = 1

Here, x=1,y=1.5,z=2
Therefore, the value of 2(x+y+z)=2(1+1.5+2)=9

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