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Question

The brakes applied to a car produce an acceleration of 6ms2 in the opposite direction to the motion. If the car takes 2 s to stop after the application of brakes, calculate the distance it travels during this time.

A
12 m
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B
10 m
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C
8 m
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D
18 m
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Solution

Step 1: Given

Accerleration: a=6 m/s2 (breaking)

Time t=2 s

Final velocity, v=0 m/s

Let s, u are distance covered and initial velocity.

Step 2: Formula used
v=u+at5
s=ut+12at2
Step 3: Finding the total distance covered
v=u+at
0=u6×2
u=12 m/s
s=ut+12at2
s=12×2+12×(6)×4
s=12m

Thus, the total distance covered before stop is 12m.

Hence, option A is correct.


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