The brakes applied to a car produce an acceleration of 6ms−2 in the opposite direction to the motion. If the car takes 2 s to stop after the application of brakes, calculate the distance it travels during this time.
Step 1: Given
Accerleration: a=−6 m/s2 (breaking)
Time t=2 s
Final velocity, v=0 m/s
Let s, u are distance covered and initial velocity.
Thus, the total distance covered before stop is 12m.
Hence, option A is correct.