The bulk modulus and the density of water are greater than those of air. With this much of information, we can say that velocity of sound in air

Is larger than its value in water

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Is smaller than its value in water

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Is equal to its value in water

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cannot be compared with its value in water

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Solution

The correct option is D
cannot be compared with its value in water

Velocity of sound in air $v_{a i r} = \sqrt{\frac{B_{a i r}}{ρ_{a i r}}}$

Velocity of sound in water $v_{w a t e r} = \sqrt{\frac{B_{w a t e r}}{ρ_{w a t e r}}}$

If only $B_{w a t e r}$ > $B_{a i r }$

Then for sure $V_{w a t e r}$ < $V_{a i r}$ .

If only $ρ_{w a t e r}$ > $ρ_{a i r}$

Then for sure $V_{w a t e r}$ > $V_{a i r}$

But if both are greater

WE can't say how the ratio's will be related

It's a maths problem.

If $\frac{B_{w a t e r}}{B_{a i r}}$ > $\frac{ρ_{W a t e r}}{ρ_{a i r}}$ ,

then we can say $V_{w a t e r}$ < $V_{a i r}$

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