Question

The % by volume of $C_4{H}_{10}$ is a gaseous mixture of $C_4{H}_{10},C{H}_4$ and $CO$ is $40$. When $200ml$ of the mixture is burnt in excess of $O_2$, Find volume (in ml) of $C{O}_2$ produced :

• A. $220$
• B. $340$
• C. $440$
• D. $560$

Answer 1

The correct option is A $220$

Since $200ml$ of mixture contains $80ml$ $C_4{H}_{10}$ and $120ml$ of $(Co+C{H}_4$)

$1$ mol, $C_4{H}_{10}$ give $4$ moles of $C{O}_2$

$80ml$, $C_4{H}_{10}$ given $320ml$ of $C{O}_2$

and $120ml$ of $(CO+C{H}_4$) gives $240ml$ Co${}_2$

Reaction-

$C_4{H}_{10}+C{H}_4+CO\stackrel{O_2}{\to }C{O}_2+H_{2}O$