The calculated bond order in $H_{2}^{-}$ ion is:

0

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1 / 2

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- 1 / 2

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Solution

The correct option is A $1 / 2$
$H_{2}^{-}$ : valence electrons= $2 + 1 = 3$
${(σ 1 s)}^{2} {(σ^{*} 1 s)}^{1}$
Bond order= $\frac{1}{2} (N_{B} - N_{A B})$
$\frac{1}{2} (2 - 1) = 0.5$

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