Question

The calculated bond order of superoxide ion $\left(O_2^{-}\right)$ is:

• A. $2.5$
• B. $2$
• C. $1.5$
• D. $1$

Answer 1

The correct option is C $1.5$

$Bondorder=\frac{1}{2}\times (N_b-N_a)$

$N_b,N_a$ are the electrons present in bonding and anti bonding orbitals repectively.

$Bondorder=\frac{1}{2}\times (8-5)$.

$Bondorder=1.5$.

Hence option $C$ is correct.