The calorific value of H2(g) at STP is 12.78kJ/L. Find the approximate standard enthalpy of formation of H2O(l).
A
−143kJ
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B
−286kJ
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C
Zero
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D
+286kJ
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Solution
The correct option is B−286kJ 1LH2(g)atSTP=122.4mol ∴ Heat released due to combustion of 122.4 mol of H2(g)=12.78kJ
Heat released due to combustion of 1 mol of H2(g) =12.78×22.4=286.27kJ ∴ standard enthalpy of formation of H2O(l)=−286kJ