The capacitance of a parallel plate air condenser is 2 μ F. A dielectric of constant 4 is introduced as shown in the figure to fill half the space between the parallel plates. Its capacitance now will be?
A
20μF
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B
3.2μF
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C
5.0μF
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D
6.4μF
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Solution
The correct option is C5.0μF C=2μFC1=C2+C1=Kϵ0A2d+ϵ0A2d=ϵ0A2d[k+1]=22[4+1]C1=5μF