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Question

The capacitance of parallel plate capacitor is 16μF. When a glass slab is placed between the plates, the potential difference reduces to 1/8th of the original value. What is dielectric constant of glass?

A
4
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B
8
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C
16
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D
32
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Solution

The correct option is B 8
Given,
16μF
V=QC=Q16μF
When dielectric is inserted
V=QC=QK(16μF)=V8
QK(16μF)=Q8×16μF
K=8
Option B is correct.

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