Question

The capacitor $2C$ is charged to potential difference $V_0$ while the capacitor $C$ is uncharged at $t=0.$ At this instant, the switch $S$ is closed.

• A. Charge on the capacitor $C$ is $\frac{2}{3}C{V}_0$ in steady state
• B. Charge on the capacitor $2C$ is $\frac{11}{3}C{V}_0$ in steady state
• C. Charge on the capacitor $C$ is $\frac{1}{3}C{V}_0$ in steady state
• D. Charge on the capacitor $C$ is $\frac{5}{3}C{V}_0$ in steady state

Answer 1

The correct option is A Charge on the capacitor $C$ is $\frac{2}{3}C{V}_0$ in steady state

$Q_1=\left(2c{v}_0\right)$

net$Q_c=\left(\frac{2c\times c}{3c}\right)=\left(\frac{2c}{3}\right)$

at steady state charge on other capacitor

$=c_{eg}v\times v$

$Q_c=\frac{2c}{3}\times v_0$