Question

The capacitor C is initially without charge. $X$ is now joined to $Y$ fir a long time, during which $H_1$ heat is produced in the resistance $R$. $X$ is now joined to Z for a long time, during which $H_2$ heat is produced in $R$ (see Figure).

• A. $H_1=H_2$
• B. $H_1=\frac{1}{2}{H}_2$
• C. $H_1=2H_2$
• D. The maximum energy stored in $C$ at any time is $H_1$.

Answer 1

Answer: (A), (D)

The correct options are
A $H_1=H_2$
D The maximum energy stored in $C$ at any time is $H_1$.

When X is joined to Y for a long time , the capacitor will full charged. The energy stored in capacitor is equal to heat produced $\left(H_1\right)$.
When X is joined to Z for a long time , the circuit is open and battery not working so the capacitor will start to discharge. After long time the energy stored in capacitor reappears as heat $H_2$.
So by energy conservation, $H_1=H_2$.
The maximum energy at any time is $H_1$.