The elements in the Cartesian product of set A×A are 9.
Thus, the elements in set A should be 3.
The pairs ( −1,0 ) and ( 0,1 ) are from Cartesian product of A×A.
The pair ( −1,0 ) belongs to A×A, so the elements −1 and 0 should be in set A.(1)
The pair ( 0, 1 ) belongs to A×A, so the elements 0 and 1 should be in set A.(2)
From equations (1) and (2), the elements −1, 0, 1 should be in set A.
A×A={ −1,0,1 } ×{ −1,0,1 } ={ ( −1,−1 ),( −1,0 ),( −1,1 ),( −1,−1 ),( 0,−1 ),( 0,0 ),( 0,1 ),( 1,−1 ),( 1,0 ),( 1,1 ) }
Thus, the remaining elements of set A×A are,
( −1,−1 ),( −1,1 ),( 0,−1 ),( 0,0 ),( 1,−1 ),( 1,0 ),( 1,1 ).