The ceiling of a hall is 40m high. For maximum horizontal distance, the angle at which the ball may be thrown with a speed of 56ms−1 without hitting the ceiling of the ball is (Take g=9.8m/s2)
A
25∘
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B
30∘
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C
45∘
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D
60∘
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Solution
The correct option is B30∘
For the range to be maximum, H≤40m ⇒40=u2sin2θ2g40=562sin2θ2×9.8sin2θ=78456×56⇒sin2θ=14⇒sinθ=0.5⇒θ=30∘