The cell reaction of a cell is: Mg(s)+cu2+(aq)⇌Cu(s)+Mg2+(aq) If the standard reduction potentials of Mg and Cu are −2.37 and +0.34V respectively. The emf of the cell is:
A
2.03V
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B
−2.03V
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C
+2.71V
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D
−2.71V
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Solution
The correct option is C+2.71V E∘Cell=E∘Cathode−E∘Anode =E∘Reducedspecies−E∘Oxidisedspecies =0.34−(−2.37)=+2.71V.