The centre of the circle passing throught $(0, 0)$ and $(1, 0)$ and touching the circle $x^{2} + y^{2} = 9$ is

\frac{1}{2}, \frac{1}{2}

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\frac{1}{2}, - \sqrt{2}

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\frac{3}{2}, \frac{1}{2}

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\frac{1}{2}, \frac{3}{2}

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Solution

The correct option is B $\frac{1}{2}, - \sqrt{2}$
Hence, Option (B) is the correct answer.

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Similar questions

The centre of the circle passing through $(0, 0)$ and $(1, 0)$ and touching the circle $x^{2} + y^{2} = 9$ can be

A circle passes through (0, 0) and (1, 0) and touches the circle $x^{2} + y^{2} = 9$ , then the centre of circle is

x^{2} + y^{2} = 9

(0, 0), (1, 0)

x^{2} +^{2} = 9

The centre of the circle passing through (0, 0) and (1, 0) and touching the circle $(x^2 + y^2 = 9\)$

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