The centroid of triangle with vertices $A (4, 5), B (2, 3), C (3, 1)$

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Solution

$A (4, 5), B (2, 3), C (3, 1)$

The centroid of triangle is
$= (\frac{4 + 5 + 3}{3}, \frac{5 + 3 + 1}{3}) = (\frac{9}{3}, \frac{9}{3}) = (3, 3)$

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