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Hydrides of Group 16

The certain i...

Question

The certain inorganic compound (X) shows the following reactions:

(i) On passing $H_{2} S$ through an acidified solution of (X), a brown precipitate is obtained.
(ii) the precipitate obtained at step(i) dissolves in excess of yellow ammonium sulphide.
(iii) On adding an aqueous solution of $N a O H$ to a solution of (X), first, a white precipitate is obtained which dissolves in excess of $N a O H$ .
(iv) The aqueous solution of (X) reduces ferric chloride. (X) is ${S n C l}_{2}$

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Solution

The inorganic compound (X) is stannous chloride ${S n C l}_{2}$ .
(i) On passing $H_{2} S$ through an acidified solution of ${S n C l}_{2}$ , a brown precipitate of SnS is obtained.
${S n C l}_{2} + H_{2} S ⟶ S n S ↓ b r o w n + 2 H C l$
(ii) the precipitate obtained at step(i) dissolves in excess of yellow ammonium sulphide to from ${N H}_{4})_{2} {S n S}_{3}$
. $S n S + ({N H}_{4} Y A S)_{2} S_{2} ⟶ ({N H}_{4} s o l u b l e)_{2} {S n S}_{3}$
(iii) On adding an aqueous solution of $N a O H$ to a solution of stannous chloride, first a white precipitate of tin(II) hydroxide is obtained which dissolves in excess of $N a O H$ to form ${N a}_{2} {S n O}_{2}$ .
${S n C l}_{2} + 2 N a O H ⟶ {S n (O H)}_{2} w h i t e ↓ 2 N a C l$
${S n (O H)}_{2} + 2 N a O H ⟶ {N a}_{2} {S n O}_{2} + H_{2} O$
(iv) The aqueous solution of (X) reduces ferric chloride to ferrous chloride and itself is oxidized to tin(IV) chloride..
${2 F e C l}_{3} + {S n C l}_{2} ⟶ {2 F e C l}_{2} + {S n C l}_{4}$

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