The chairs in three rooms of an auditorium are in the ratio 2:3:5. If 20 chairs were added to each room, the ratio changes to 4:5:7. The total number of chairs in the auditorium before the increases was

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

150

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 100
The number of chairs before increase is
2x+3x+5x
The number of chairs after increase
2x+3x+5x+60 = 4y+5y+7y
2x+20=4y $\to$ (1
3x+20=5y $\to$ (2
(2-(1
x = 10
Total number of chairs before increasep;
= $10 \times 10 = 100$

Suggest Corrections

Similar questions

In an auditorium, the number of rows is equal to the number of chairs in each row. If the capacity of the auditorium is 2025, find the number of chairs in each row.

Q. In a room there are x² rows of chairs and each two contains 2x² chairs. The total number of chairs in the room is

(a) 2x³
(b) 2x⁴
(c) x⁴
(d)

\frac{x^{4}}{2}

In a school auditorium, the number of chairs in a row is the same as the number of rows of chairs. There are 7033 students in the school. If we know that less than 31 chairs were empty, how many chairs were empty after all the students sat down?

12

chairs were arranged with

3

chairs in each row. Later,

8

more chairs were added. Find the number of chairs in each row such that the total number of rows remains the same.

Q. In a classroom, there are 7 rows of chairs. Each row has 5 chairs. What is the total number of chairs in the classroom?

Join BYJU'S Learning Program

The chairs in three rooms of an auditorium are in the ratio 2:3:5. If 20 chairs were added to each room, the ratio changes to 4:5:7. The total number of chairs in the auditorium before the increases was

The correct option is B 100The number of chairs before increase is 2x+3x+5x The number of chairs after increase 2x+3x+5x+60 = 4y+5y+7y 2x+20=4y → (1 3x+20=5y → (2 (2-(1 x = 10 Total number of chairs before increasep; = 10×10=100

The correct option is B 100
The number of chairs before increase is
2x+3x+5x
The number of chairs after increase
2x+3x+5x+60 = 4y+5y+7y
2x+20=4y $\to$ (1
3x+20=5y $\to$ (2
(2-(1
x = 10
Total number of chairs before increasep;
= $10 \times 10 = 100$