The change in velocity of a motorbike is 54 km/hr in one minute. Calculate the acceleration in m/ $s^{2}$ and km/ ${h r}^{2}$

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Solution

Given,

Velocity of the motorbike is $54km/hr

So, the acceleration in $k / h r^{2}$ is:

$\frac{56}{\frac{1}{60}} = 54 \times 60$

$= 3240 k m / h^{2}$

And,

The acceleration in $m / s^{2}$ is:

$\frac{3240 \times 1000}{3600 \times 3600}$

$= .25 m / s^{2}$

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The change in velocity of a motorbike is 54 km/hr in one minute. Calculate the acceleration in m/s2 and km/hr2

Given,Velocity of the motorbike is $54km/hrSo, the acceleration in k/hr2 is:56160=54×60=3240km/h2And, The acceleration in m/s2 is:3240×10003600×3600=.25m/s2

The change in velocity of a motorbike is 54 km/hr in one minute. Calculate the acceleration in m/ $s^{2}$ and km/ ${h r}^{2}$

Given,

Velocity of the motorbike is $54km/hr

So, the acceleration in $k / h r^{2}$ is:

$\frac{56}{\frac{1}{60}} = 54 \times 60$

$= 3240 k m / h^{2}$

And,

The acceleration in $m / s^{2}$ is:

$\frac{3240 \times 1000}{3600 \times 3600}$

$= .25 m / s^{2}$