Question

The change $P_2{O}_5\to H_4{P}_2{O}_7$ is an :

• A. oxidation process
• B. reduction process
• C. neither Oxidation nor reduction process
• D. redox process

Answer 1

The correct option is C neither Oxidation nor reduction process

Oxidation number of $P_2{O}_5$: $2x+(-10)=0$

$\Rightarrow 2x=10$

$\Rightarrow x=5$.

Oxidation number of $P$ in $H_4{P}_2{O}_7$: $4+2x+(-14)=0$

$\Rightarrow 2x=14-4$

$\Rightarrow x=5$.

Since, oxidation is loss of electron and reduction is gain of electron and Redox reaction is when both oxidation & reduction take place simultaneously. Therefore, It is neither oxidation nor a reduction process.